A sample of a gas has a volume of 426mL at 330 K. What temperature is necessary for the gas to have a volume of 475 mL? Remember to convert mL to L. Round to the nearest whole number.

Question

A sample of a gas has a volume of 426mL at 330 K. What temperature is necessary for the gas to have a volume of 475 mL? Remember to convert mL to L. Round to the nearest whole number.

Answer 1

Apply Charles' Law, V₁/T₁ = V₂/T₂

V₁ = 426 mL = 0.426 L

V₂ = 475 mL = 0.475 L

T₁ = 330 K

T₂ = unknown

Substitute the values in the above equation, T₂ = (0.475)(330)/(0.426) = 368 K