If I have 7 moles of a gas at a pressure of 4.6 atm and a volume of 14 liters, what is the temperature?

Answer 1

Hi there! We need to use the ideal gas law:

PV = nRT

(4.6 atm)*(14 L ) = (7 moles)(.0821 L atm/(mol K))*T

T = (4.6 * 14) / (7 * 0.0821) = 112.5 K (Temperature is in Kelvin)

Hope this helps!