What is the pressure in atm. of 18.4 g of CO2 in a 13.5 L container at 30.0oC

Answer 1

Find the moles of gas: 18.4 g CO₂ (1 mole/ 44.01 g) = .41809 moles of CO₂

Now you can use the ideal gas law:

PV = nRT

or

P = nRT/V where n is moles of any ideal gas, R is .0821 l-atm/mole-Kelvin, T is temperature in Kelvin ( 273 + °C) and V is volume in liters. This will give P in atmospheres.

Good luck!