How many moles of SO2 are present in a 2.22 L cylinder if the temperature is 150.0oC and the pressure is 5.53 atm?

Answer 1

PV=nRT. P = 5.53 atm, V = 2.22L, and T = 150C, which you need to convert to K, so 423 K. Based on the units provided, an R = 0.0821 Latm/molK would make sense to use.

n = PV/RT = 5.53 atm * 2.22 L / (0.0821 Latm/molK * 423 K ) = 0.354 mol.

Hopefully this makes sense - let me know if you have any questions.

Answer 2