
Stephanie R. answered 03/25/20
Experienced AP Chemistry Teacher
First you need to realize that this is a stoichiometry problem that requires a balanced chemical equation. Since CO2 is produced from CH4 and O2, this will be a combustion reaction with water as the other product.
The equation should look like this: CH4 + O2 → CO2 + H2O
and balanced it should look like this: CH4 + 2 O2 → CO2 + 2 H2O
Now we can start the stoichiometry! Stoichiometry is a mole-mole ratio of two or more species in a balanced chemical reaction. It allows you to convert the moles of one species to the moles of another. Since the problem gives you the mass of methane, the first stoichiometry step is to convert it to moles, then you can look at the mole-mole ratio.
The first step should look like this:
72 g CH4 x 1 mol CH4 / 16 g CH4 = 4.5 mol CH4
The next step is to convert the moles of CH4 to moles of CO2:
4.5 mol CH4 x 1 mol CO2 / 1 mol CH4 = 4.5 mol CO2
In that mole-mole step I used 1 mole for CO2 and 1 mole for CH4 because there was no number in front of CO2 or the CH4 in the balanced equation, which is the same as a 1. You may be tempted to skip this step because the 1's cancel out, but DON'T DO IT! That step is the most important step of stoichiometry and just because it coincidentally turned out not to matter to this problem, it likely will matter in the next problem and it is good to remember that this step exists.
If you put both steps together, you have a stoichiometry problem:
72 g CH4 x 1 mol CH4 / 16 g CH4 x 1 mol CO2 / 1 mol CH4 = 4.5 mol CO2
The answer is 4.5 mol CO2
J.R. S.
03/25/20