Argon gas in a storage tank has a volume of 225 L at 643kPA and 24.6 C. How many moles of argon gas are in the tank?

Answer 1

With the ideal gas equation PV = nRT, number of moles n = PV/RT = (643 kPa)*(225 L) / [(8.314 kPa*L/mol K)*(24.6 + 273.1 K)] = 58.5 moles.