What is the solubility of AgCl in 0.010 M NaCl?

Question

The K_sp of AgCl is 1.6 x 10^-10. What is the solubility of AgCl in 0.010 M NaCl? Give your answer using scientific notation and to 2 significant figures 

The answer is 1.6*10^-8

Answer 1

AgCl <--> Ag⁺ + Cl^-

In 0.01 M NaCl, the [Cl-] = 1 x 10^-2

Ksp = [Ag⁺]*[Cl^-]

1.6 x 10^-10 = x*(1x10^-2)

x = 1.6 x 10^-10+2 = 1.6 x 10^-8 M Ag⁺