Zn + CuCl2 --> ZnCl2 + Cu How many grams of ZnCl2 will be produced from 15.00g of Zn and 7.00g of CuCl2?

Answer 1

First you'd need to find the limiting reagent by finding moles of each of the reactants.

Once you've done that you'll find that CuCl₂ is the limiting reagent.

You can only produce as many moles of a product as your limiting reagent allows.

Thus by multiplying the moles of the limiting reagent by the molecular weight of your product you will find the mass of the produced ZnCl_2.

I found the mass of ZnCl₂ produced was very close to 7 grams (7.096 g)