Conditional Statements In C Programmin

Question

Question 1

1.Given the following code:

switch(x - y) {

case 0:

return x;

case 4:

break;

case 7:

x = x - 1;

case 9:

return x*y;

case 3:

default:

return y - x;

}

return y;

}

What does g(9, 5) evaluate to?

2.Question

Consider the following code:

if (x + 2 < y) {

x = x + 3;

return y * x;

else {

return x + y + 2;

What does f(5, 10) evaluate to?

Answer 1

ASSUMING the switch statement is inside function int g( int x , int y),

then the return value shall be 5.

for x=9 and y=5, x-y=9-5=4, so case 4 in the switch gets executed, which

does nothing except break; 5 gets returned following the switch

The same ASSUMPTION for problem #2, is that the switch lies inside function int f( int x, int y)..

the function will then return 80...

for x=5 and y=10, x+2 < y ---> 5+2 < 10 ---> 7 < 10 is true;

so then x becomes 5+3=8

finally 8*10 = 80 is returned

also note there is } missing, so that shall be a compile error; even though it

is technically unreachable code, some compilers will demand it... I'm using Bloodshed Dev C++

and it caused a compile error despite the fact it is unreachable

Here is the complete code:

#include <stdio.h>

int g(int x, int y)

{

switch(x - y)

{

case 0:

return x;

case 4:

break;

case 7:

x = x - 1;

case 9:

return x*y;

case 3:

default:

return y - x;

} //switch

return y;

}

int f( int x, int y)

{

if (x + 2 < y)

{

x = x + 3;

return y * x;

} //compile error: missing }

else {

return x + y + 2;

}

}

int main()

{

printf("%d \n",g(9,5));

printf("%d \n ",f(5,10));

}