How many grams of MgCl2 will be produced from 16.0g of Mg(OH)2 and 11.0g of HCl

Answer 1

This is a limiting reactant problem. The brute force way to do this is to do a g->mole->mole-> gram for both reactants. Whichever produces the least product in the LR and that is the answer.

You need the rxn staement : Mg(OH)₂ + 2HCl --> MgCl₂ + 2H₂O

You need the molar masses of Mg(OH)₂, MgCl₂, and HCl

I will do the process for Mg(OH)₂ and leave HCl to you:

16 g Mg(OH)₂ (1mole/ 58.32 g)(1mole MgCl₂/1 mole Mg(OH)₂)( 95.2 g/mole) = 26.12 g MgCl₂ (Not necessarily the answer)

Good luck!