Denise G. answered 03/19/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
The way to do this is:
lim h->0 [f(x+h)-f(x)]/h
Using the function you provided:
[(x+h)2+(x+h)-(x2+x)]/h FOIL the first term and distribute the -1
[x2+2xh+h2+x+h-x2-x]/h Simplify the numerator by combining like terms
[2xh+h2+h]/h Factor an h in the numerator
h(2x+h+1)/h Cancel the h in the numerator and denominator
2x+h+1
Now, I will evaluate using the limit
The way to do this is:
lim h->0 2x+h+1
2x+1