What is the theoretical yield of BaSO4 for 1.25g if barium nitrate

Question

A student combines 1.25g of barium nitrate with an excess excess of sodium sulfate in order to make barium sulfate. What is the theoretical yield of BaSO4 for this reaction? the balance equation is

Ba(NO3)2+Na2SO4->BaSO4+2NaNO3

Answer 1

Divide the given mass of Ba(NO3)2 by its molar mass to find the number of moles that will be reacting. The balanced equation shows that for each mole of Ba(NO3)2 that reacts, one mole of BaSO4 is produced, so the name number of moles of BaSO4 will be formed. Lastly, multiply by the molar mass of BaSO4 to get your final answer.