What is the net ionic equation including physical states of Li2SO4(aq)+AgNO3(aq)

Answer 1

This would be a double replacement reactions so the metals will switch places and you balance based on the charges: Li(+1), Ag (+1), SO₄(-2), NO₃(-1)

Li₂SO_4(aq)+AgNO_3(aq) →Ag₂SO₄+LiNO₃

No we look at our solubility rules are either of the products insoluble?

Ag₂SO₄ is insoluble so will be a solid, but LiNO₃ is aqueous

Li₂SO_4(aq)+AgNO_3(aq) →Ag₂SO_4(s)+LiNO_3(aq)

Then we balance our reaction, do we have any with different amounts on each side? How do we fix it?

1 Ag on left, 2 on right

2 Li on left, 1 on right

Li₂SO_4(aq)+2AgNO_3(aq) →Ag₂SO_4(s)+2LiNO_3(aq)

Since with both of those changes we doubled our NO₃ we are sill balanced on our anions so we are good to continue.

Break into complete ionic equation but writing (aq) compounds as their separate ions

2Li⁺_(aq)+SO₄^2-_(aq)+2Ag⁺_(aq)+2NO₃^-_(aq) →Ag₂SO_4(s)+2Li^-_(aq)+2NO₃^-_(aq)

If we look Li⁺ and NO₃^- are in solution on both sides so nothing is changing for them, they are spectator ions because they just "watch" the reaction so we cut them out.

SO₄^2-_(aq)+2Ag⁺_(aq) →Ag₂SO_4(s)

We are left with our Net Ionic equation showing only what is actually reacting.