
Seth F. answered 03/17/20
PhD Student in Chemistry with 5+ Years of Tutoring Experience
To answer this question we need to realize a couple things.
Given constant volume the following holds true.
- qrxn = -qcalorimeter
- qcalorimeter = (heat capacity of calorimeter) x (ΔT)
qcal = (6.97 kJ / oC ) x (10 oC) = 69.7 kJ
qrxn = -69.7 kJ
Technically this answers your question but given the information in the question given I assume it probably will ask for the answer in (kJ/mol)
1.14g octane (1mol octane / 114g octane) = 0.01 mol octane
qrxn (kJ/mol) = (-69.7 kJ) / (0.01 mol octane)
qrxn = -6970 kJ / mol of octane