A graduated cylinder contains 17.5 mL of water. What is the new water level after 32.8 g of silver metal with a density of 10.5 g/mL is submerged in the water?

Answer 1

Increase in water level = Volume of the submerged silver.

 

ΔV = volume of silver

 

ΔV = m/ρ = (32.8 g)/(10.5 g/mL) ≅ 3.12 mL

 

V = final water level

 

V = (17.5 + 3.12) mL ≅ 20.6 mL