Chemistry lab 1211

Question

⦁ Describe how to prepare 100 mL of 0.35 M copper (II) sulfate solution. Be sure to specify all glassware and instrumentation needed.

Answer 1

Molecular weight of copper (II) sulfate = 159g * 60g

Molarity = (moles of solute)/(volume in Liters)

Mole = weight/molecular weight

0.35 = (x/15*60)/(100/1000L)

0.35 = (x * 1000)/(15*60*100)

x=5.589g

We need:

(1) 5.589g of solid copper (II) sulfate

(2) distilled water

(3) 100ml standard flask

(4) funnel (to transfer water)