
Samuel F. answered 03/11/20
Chemical Engineer with 5+ Years of Tutoring Experience
Hello Eli!
For this question, let's write the equations of solubility:
Al(OH)3(s) ↔ Al3+(aq) + 3OH-(aq)
Q = [Al3+] * [OH-]3
Pb(OH)2 (s) ↔ Pb2+(aq) + 2OH-(aq)
Q = [Pb2+] * [OH-]2
If Q > Ksp then it will precipitate.
For the Al(OH)3 we'll have:
[Al3+] * [OH-]3 > 4.6 . 10-33
0,45 * [OH-]3 > 4.6 . 10-33
[OH-]3 > 1.022 . 10-32
[OH-] > 2.17 . 10-11
pOH > 10.66
pH > 3.33
For the Pb(OH)2 we'll have:
[Pb2+] * [OH-]2 > 1.43 . 10-20
0,26 * [OH-]2 > 1.43 . 10-20
[OH-]2 > 5.5 . 10-20
[OH-] > 2.34 . 10-10
pOH > 9.63
pH > 4.37
For the
3.33 < pH < 4.37 only the Al(OH)3 will precipitate
Eli S.
Thank you so much, Samuel!03/11/20