Tiffany W. answered 03/11/20
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V1 = 3.63L
V2 = 6.00L
P1 = 7.74atm
T = 273K
P1V1/ T1 = P2V2/T2
P1V1T2 / T1V2 = P2
((7.74atm)(3.63L)(273K)) / ((273K)(6.00L)) = P2
4.68 = P2
4.68 atm
Ariel G.
asked 03/10/20A certain mass of nitrogen gas occupies a volume of 3.62 L at a pressure of 7.74 atm. At what pressure will the volume of this sample be 6.00 L? Assume constant temperature and ideal behavior.
Tiffany W. answered 03/11/20
Unlock Academic Success with a Calm, Personalized Approach
V1 = 3.63L
V2 = 6.00L
P1 = 7.74atm
T = 273K
P1V1/ T1 = P2V2/T2
P1V1T2 / T1V2 = P2
((7.74atm)(3.63L)(273K)) / ((273K)(6.00L)) = P2
4.68 = P2
4.68 atm
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