Michael C. answered 01/31/15
Tutor
New to Wyzant
Software engineer offering math and computer tutoring
C = num of child tickets ($2)
A = num of Adult tickets ($4)
2C + 4A = $12,600
C + A = 3500 (total tickets sold)
solve C in terms of A and substitute back into the 1st equation
C = 3500 - A
2(3500 - A) + 4A = $12,600
7000 - 2A + 4A = $12,600
7000 + 2A = $12,600
2A = 5600
A = 2800 @ $4
C + 2800 = 3500
C = 700 @ $2
A = num of Adult tickets ($4)
2C + 4A = $12,600
C + A = 3500 (total tickets sold)
solve C in terms of A and substitute back into the 1st equation
C = 3500 - A
2(3500 - A) + 4A = $12,600
7000 - 2A + 4A = $12,600
7000 + 2A = $12,600
2A = 5600
A = 2800 @ $4
C + 2800 = 3500
C = 700 @ $2