Step 1: 10g AgNO3 * (1mol AgNO3/169.9g AgNO3) = 0.059mol
Step 2: 0.059mol/0.5L =.118M
Final Answer: 0.12M
Joey R.
asked 03/06/20Step 1: 10g AgNO3 * (1mol AgNO3/169.9g AgNO3) = 0.059mol
Step 2: 0.059mol/0.5L =.118M
Final Answer: 0.12M
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Joey R.
thank you03/06/20