How many grams of ZnCi2 will be produced from 22.0 g of Zn and 14.0 g of HCI

Answer 1

Step 1: Write out the chemical equation and balance it

Zn + 2 HCl --> ZnCl₂ + H₂

Step 2: Find the moles of product that each reactant could make individually to determine the limiting reactant

22.0 g Zn x (1 mole Zn / 65.38g Zn) x (1 mole ZnCl₂ / 1 mole Zn) = .336 moles ZnCl₂

14.0 g HCl x (1 mole HCl / 36.46 g HCl) x (1 mole ZnCl₂ / 2 moles HCl) = .192 moles ZnCl₂

HCl is the limiting reactant

Step 3: Use the limiting reactant to determine how much product you can create

.192 moles ZnCl₂ x (136.29g ZnCl₂ / 1 mole ZnCl₂) = 26.17 g ZnCl₂