Andrew H. answered 02/28/20
High School Physics/Math Tutor
Remember that the electric field equation is E = kq/r2, which is different from the Coulomb force equation that is FE = k|Qq|/r2.
Yogita S.
asked 02/28/20The solution here says to figure it out by using cos theta as a factor, but I don't understand why I cannot just break it up into components?
Figure shows two charge particles on an x acis -q on the -x side with a magnitude -3.20*10^-19 at x=-3.0m and a positive q and x=3.0 m on the x axis. Point P is located at 4.0 m on the y axis. What are teh magnitude nd direction of the net electric field at point P?
Andrew H. answered 02/28/20
High School Physics/Math Tutor
Remember that the electric field equation is E = kq/r2, which is different from the Coulomb force equation that is FE = k|Qq|/r2.
Wiwi S. answered 02/28/20
Experienced Teaching Assistant Specializing in Math and Physics
You can solve it by breaking E-field into Ex and Ey. We know Ey will be 0. And the Ex from both particles will have the same magnitude and direction. Then we just do the calculation and get Ex in the order of magnitude of 10^-10.
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.