Point slope firm and slope intercept

Question

Through: -5,-3 and parallel to y=8/5x-3

Answer 1

Hello Tucker,

The point slope form of a linear equation is

y-y1=m(x-x1)

The y-intercept form of a linear equation is

y=mx+b, where m is the slope and b is the y-intercept

Given point (-5,-3) [(x1,y1)] and the line must be parallel to y=8/5x-3 [y=mx+b]:

Because the question calls for a line parallel to the given line y=8/5x-3, the slope of the line that we are seeking will have the same slope. (Think railroad tracks).

Thus m = 8/5

Using the point slope formula

y-y1=m(x-x1)

y-(-3)=8/5(x-(-5))

y+3=8/5(x+5)

Use the point slope and solve for y.

Y+3=8/5x+40/5

Y+3=8/5x+8

Y=8/5x+5

The Line is now in y=mx+b format.

If you were to graph this line: y+3=8/5(x+5)

and this line: Y=8/5x+5

you would discover they are two different ways of expressing/describing the same line.