Margaret C. answered 02/25/20
PhD in Chemistry with 15+ Years of Teaching Experience
q = m c ΔT = 585.0 g x 0.3850 J/gC x (21.17-13.74)C = 1673J
Marcella J.
asked 02/24/20How much energy would it take to heat a section of the copper tubing that weighs about 585.0 g , from 13.74 ∘C to 21.17 ∘C ? Copper has a specific heat of 0.3850 (J/g)⋅∘C
Express your answer to four significant figures.
Margaret C. answered 02/25/20
PhD in Chemistry with 15+ Years of Teaching Experience
q = m c ΔT = 585.0 g x 0.3850 J/gC x (21.17-13.74)C = 1673J
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