Touba M. answered 02/24/20
B.S. in Pure Math with 20+ Years Teaching/Tutoring Experience
Hi Cheyanna,
First: find the intersect between given line and curve y = x2 - 4x and y = x - 4.
x - 4 = x^2 -4x
x - 4 -x^2 + 4x = 0
-x^2 +5x -4 = 0
-( x - 1) (x - 4 ) = 0
x - 1 =0 ----> x = 1 and x - 4 = 0 -------> x = 4 these numbers are the bounded of integral
Area = ∫(-x^2 +5x -4) dx = - ∫(x^2 -5x +4) dx it is easy to take negative of the expression
Area = - ( 1/3 x^3 - 5/2 x^2 +4x ) from x =1 to x = 4
Area = - ( 64/3 - 5/2 *16 +16 ) + ( 1/3 -5/2 +4) = -63/3 +40 -16 -2.5 + 4 = -21 +40 -16 -2.5 +4 = 4.5
I hope it is useful,
Minoo