
Yefim S. answered 02/24/20
Math Tutor with Experience
Answer is 2): Area S = = (tanx + cosx) with substitution from x = 0 to x = π/4.
S = (tanπ/4 + cosπ/4) - (tan0 + cos0) = 1 + 1/21/2 - 0 - 1 = sqrt2/2
Cheyanna B.
asked 02/24/20Which of the following integrals represents the area of the region bounded in the first quadrant by x = and the functions f(x) = sec2(x) and g(x) = sin(x)?
Options:
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Yefim S. answered 02/24/20
Math Tutor with Experience
Answer is 2): Area S = = (tanx + cosx) with substitution from x = 0 to x = π/4.
S = (tanπ/4 + cosπ/4) - (tan0 + cos0) = 1 + 1/21/2 - 0 - 1 = sqrt2/2
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