Find the value of k such that (2,0) is an x-intercept for the graph of f(x)=kx^5-x^2+5x+8

Answer 1

Substitute the point (2,0) into the function and solve for k. F(2)=0= k*2^5-2^2+5*2+8=32k-4+10+8= 32k+14=0 .. thus k =-7/16