One end of a pool is a verticle wall 16 ft wide.

Question

One end of a pool is a verticle wall 16 ft wide. What is the force exerted on this wall by the water if it is 7 ft deep? The density of water is 62.4 lb/ft^3.

Answer 1

The force on the wall will be the pressure at the centroid of the wetted area times the wetted area. The centroid of a rectangle is located at the height/2, thus 7/2 = depth of 3.5 feet. The pressure is = gamma * depth = 62.4*3.5= 218.4 lbs/f^2. The force = 218.4*7*16= 24460.8 lbs