How many grams of NH3 can be produced from 3.63 mol of N2 and excess H2.

Question

3H2(g)+N2(g)→2NH3(g)

How many grams of NH3 can be produced from 3.63 mol of N2 and excess H2.

How many grams of  are needed to produce 13.43 of NH3 ?

How many molecules (not moles) of NH3 are produced from 2.298 *10^-4 g of H2?

Answer 1

The coefficients in front of each compound represent the molar ratios. This means for every 3 moles of H₂ there is one mole of N₂ and 2 moles of NH₃. So if you have 3.63 moles of N₂ , change that to NH₃ using the molar conversion (important, this must be in moles, so if they had given grams, you had to convert to moles first). Sop 3.63 moles of N₂ x (2 moles of NH₃/1 moles of N₂) means there are 7.26 mols of NH₃ (the moles of N₂ go on the bottom of this conversion because we started with N₂ and want to cancel those out so we end up with NH₃).

You can do the same for the other parts. You just have to convert the grams to moles before using the molar ratios to convert.

For the last part, 1 mole=6.022x 10²³ molecules. Use that conversion