How many grams of CaCl2 are produced when 7.00 moles of HCl react with excess Ca(NO3)2? Ca(NO3)2 + 2HCl → CaCl2 + 2HNO3

Question

all i need is how many grams of CaCl2 are produced when 7 moles of HCl react with excess Ca(NO3)2

thanks in advance!

Answer 1

The balanced equation says ... for every 2 moles of HCl you will get 1 mole of CaCl2, that means for 7 moles of HCl, you will get 3.5 moles of CaCl2.

Now all you need to do is to convert the moles of CaCl2 to grams of CaCl2.

Remember moles = mass/molar mass

So mass of CaCl2 = Moles of CaCl2 X Molarmass of CaCl2

mass of CaCl2 = 3.5 mol X 110.9 g/mol = 388.15 g CaCl2

Answer 2

(1 mole CaCl₂/ 2 moles HCl)*7 moles HCl *(110.984g/1 mol CaCl₂) = 388.4 g = 388 g CaCl₂