Write the balanced equation for the neutralization reaction between H2SO4 and KOH in aqueous solution. Phases are optional.

Answer 1

An acid and a base with react together to form water and a salt -- we call this type of reaction a neutralization reaction. In this case our acid is sulfuric acid (H₂SO₄) and our base is potassium hydroxide (KOH).

acid + base --> water + salt

H₂SO_{4 (aq)} + KOH _(aq) --> water + salt

Now this is also a double replacement reaction, the H⁺ from the H₂SO₄ will attach to the OH^- from the KOH to make H₂O (water). Likewise, the K⁺ will stick to the SO₄^2- to make Na₂SO₄ salt.

H₂SO_{4 (aq)} + KOH _(aq) --> H₂O _(l) + K₂SO_{4 (aq)}

Now let's add coefficients to balance the number of atoms on each side. I have one K on the left and two on the right, so we can add 2 in front of KOH. Now we have four H's on the left and two on the right, so we can add a 2 in front of H₂O to get our balanced equation.

H₂SO_{4 (aq)} + 2KOH _(aq) --> 2H₂O _(l) + K₂SO_{4 (aq)}

This reaction is also really exothermic, so heat is released.

Note for another reaction

If you have less KOH than you have H₂SO₄, then it is possible to get the reaction

H₂SO_{4 (aq)} + KOH _(aq) --> H₂O _(l) + KHSO_{4 (aq)}

Where HSO₄^- anion remains in solution attached to the K⁺.