Which integral gives the area of the region in the first quadrant bounded by the graphs of y^2 = x - 1, x = 0, y = 0, and y = 2?

Question

Question options:

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Answer 1

Answer is 1). But this integral easer to do along y-axis; Area = ∫₀²(y² + 1)dy = (y³/3 + y)₀² = 2³/3 + 2 = 14/3