How many atoms are in 4.27 mol of pure aluminum?

Answer 1

To calculate this, you need to know the concept of Avogadro's number. Avogadro's number states that one mole of any substance contains 6.022 * 10²³ number of atoms. That means 1 mol of Helium, 1 mole of Copper, 1 mol of gold, and 1 mol of Aluminum, all contain 6.022 * 10²³ number of atoms.

Therefore, 4.27 mol of pure Aluminum will have 4.27 * 6.022 * 10²³ number of atoms. This number is 2.57 * 10²⁴.

Good luck and hope this helps!