
Eli F. answered 02/05/20
Calculus AB, BC, 1, or 2
So I should preface this with was not able to get one of the answer choices. I hope someone can see my error or maybe the answer is not an option.
First I want to choose 1 - x as my u
u = 1 - x
then find du
du = -1
To solve this we will also need to find x
u = 1 - x
x = 1 - u
With this we will substitute back into the integral
int( (1 - u) (u)^(1/2) (-1du)
Next we will pull the negative 1 out in front of the integral as it is a constant. We will also distribute the u^(1/2)
-int( (u^(1/2)) - (u^(3/2)) du)
Next take the integral and add the integral constant
-[ 2/3(u^(3/2)) - 2/5(u^(5/2)) ] + C
Next distribute the negative and substitute 1 - x for u
2/5(1 - x)^(5/2) - 2/3(1 - x)^(3/2) + C