Inactive Tutor answered 02/05/20
Tutor
New to Wyzant
To evaluate this integral we use substitution: t = x5
Then dt = 5x4dx, and = ∫dt/sqrt(1 - t2) = sin-1t + C = sin-1t + C = sin-1(x5) + C.
Answer is 1)
Daniel M.
asked 02/05/20Evaluate
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Question options:
| 1) | sin-1(x5) + C |
| 2) | cos-1(5x) + C |
| 3) | ![]() |
| 4) | The antiderivative cannot be found |
Inactive Tutor answered 02/05/20
To evaluate this integral we use substitution: t = x5
Then dt = 5x4dx, and = ∫dt/sqrt(1 - t2) = sin-1t + C = sin-1t + C = sin-1(x5) + C.
Answer is 1)
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