Sanjay S. answered 01/29/15
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Amber/Linda,
It looks to me that what is being asked is
x - 12*1/(x) = 1
or
x^2 -x -12 = 0
x^2 - 4x + 3x -12 = 0
x(x-4) +3(x-4) = 0
(x-4)(x+3) = 0
x = 4 and x = -3
Linda C.
01/29/15