Braxton F.

asked • 01/30/20

Find d/dx for the equation

Find the derivative with respect to x of the integral from 1 to 4x of the square root of the quantity x squared plus 1, dt .

Question options:

1) the square root of the quantity 4 times x plus 1

2)  the sum of the square root of the quantity 16 times x squared plus 1 and the square root of 2

3)  the product of 4 and the square root of the quantity 16 times x squared plus 1

4)  the square root of the quantity 16 times x squared plus 1


Paul M.

tutor
Are you sure you have copied the problem correctly? There is no t in the integrand.
Report

01/30/20

Stanton D.

Yeah -- even if you made it a dx, the four choices are way under-complex for the suggested function set, by my reckoning -- has to do with the complexity introduced by the (x^2+1)^0.5 integral. -- Cheers, -- Mr. d.
Report

01/30/20

Patrick B.

the integral is with respect to t, not x. so sqrt(x^2+1) factors out. the integral of dt is t; the limits of integration get you 4x-1 so the function becomes (4x-1) * sqrt(x^2+1) The derivative via product rule is: (4x-1) (1/2)(x^2+1)^(-1/2)(2x) + 4sqrt(x^2+1) = x(4x-1)/ sqrt(x^2+1) + 4*sqrt(x^2+1) = [4x^2 - x + 4*(x^2+1) ]/ sqrt(x^2+1) = (8x^2 -x + 4]/sqrt(x^2+1) None of the above
Report

02/02/20

1 Expert Answer

By:

Arturo O. answered • 02/08/20

Tutor
5 (1)

College lead calculus tutor.

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.