Inactive Tutor answered 02/02/20
Tutor
New to Wyzant
integral (1-x),x=[0,1] + integral(x-1) , x=[1,2]
[ x - (1/2)x^2 ], x = [0,1] + [ x^2 - x], x=[1,2]
(1 - 1/2) + (4-2) = 1/2 + 2 = 5/2
Braxton F.
asked 01/30/20Evaluate
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Inactive Tutor answered 02/02/20
integral (1-x),x=[0,1] + integral(x-1) , x=[1,2]
[ x - (1/2)x^2 ], x = [0,1] + [ x^2 - x], x=[1,2]
(1 - 1/2) + (4-2) = 1/2 + 2 = 5/2
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