∫sin x dx/cos2x
let u = cos x then du = -sin x dx
= -∫du/u2 = 1/u = 1/cos x = sec x
George J.
asked 01/29/20Evaluate the integral .
Question options:
1) | 2ln|1 - sin2(x)| + C |
2) | -csc(x) + C |
3) | sec(x) + C |
4) | None of these |
∫sin x dx/cos2x
let u = cos x then du = -sin x dx
= -∫du/u2 = 1/u = 1/cos x = sec x
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.