Sue P.
asked 01/21/20Le Chatelier's Principle
Please explain what happens when NaNO3 is added to a saturated CuCl2 aq solution. The CuCl2 solution is blue and then turned a very dark green black when the NaNO3 was added. I understand there is not a common ion effect but was wondering if the Na+ ions capture some to the Cl- ions to lower the Cl- concentration. This would then shift the equilibrium to towards the left/ reactants ( Cu+2 aq + Cl-1 aq -->/<--- CuCl42+ aq). I guess I was expecting more of a dark blue color change.
1 Expert Answer
Jesse E. answered 01/22/20
Masters in Chemistry and Bachelors in Biology
The reaction is trying to proceed toward the product side assuming when you state the CuCl2 solution, you mean there is not any NaNO3. If you add the NaNO3 to the solution, this would cause the the following reaction to occur:
CuCl2(aq) + 2NaNO3(aq) <=> Cu(NO3)2(aq) + 2NaCl(aq)
As you can see, this is a simple displacement reaction where the ions are exchanged. If you want me to further explain this, please let me know.
Sue P.
Thank you. Yes, the solution was only CuCl2 and appeared light blue in color. Then, solid NaNO3 was added and there was a color change. I was just trying to figure out why it turned dark swampy green and its relationship to the equilibrium shift. Perhaps the color change has nothing to do with Le Chatelier's and is just the double replacement reaction. The experiment before involved adding only NaCl to the CuCl2 and was easy to predict the solution would turn green (more CuCl4 in solution produced to counterbalance the increased Cl- to return to equilibrium) because of the common ion effect with more Cl ions. Thanks again for your help.01/22/20
J.R. S.
01/22/20
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J.R. S.
01/21/20