
William W. answered 01/19/20
Experienced Tutor and Retired Engineer
Using the chain rule,
For the first term (g'(f(2x)) since x = 1, then 2x = 2*1 = 2 so f(2x) = f(2) and according to the table f(2) = 1 and g'(1) = 4 so the first term equals 4
For the 2nd term (f'(2x)), since x = 1, then 2x = 2*1 = 2 so f'(2x) = f'(2) and according to the table f'(2) = 1 so the 2nd term equals 1
The 3rd term just equals 2
so (g(f(2x))' = 4*1*2 = 8