Arthur D. answered 01/18/20
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
s=6t^2+2t over interval [1,4]
use [f(b)-f(a)]/[b-a] where [1,4]=[a,b]
[s(4)-s(1)]/(4-1)
s(4)=6*4^2+2*4=96+8=104
s(1)=6*1^2+2*1=6+2=8
(104-8)/3
96/3
32 mh-1