
William W. answered 01/17/20
Experienced Tutor and Retired Engineer
I think I've got the picture:
The limit DNE as x approaches -2 because it does not approach a number from both sides.
The limit does exist as x approaches -1 because it does get closer and closer to a number (it is immaterial that f(-1) = 2).
The limit does exist as x approaches 0
The limit DNE as x approaches 1
The limit does exist as x approaches 2
The limit DNE as x approaches 3
The limit does exist as x approaches 4
The limit DNE as x approaches 5
So the limit exists at x = -1, 0, 2, and 4