
Zera M.
asked 01/12/20chem 151 mass and density
Calculate these masses.
(a)
What is the mass (in g) of 5.75 cm3 of palladium, density = 12.00 g/cm3?
(b)
What is the mass (in g) of 30.0 mL cyclohexane, density = 0.779 g/cm3?
3 Answers By Expert Tutors

William W. answered 01/13/20
Math and science made easy - learn from a retired engineer
Density = mass/volume
D = m/V
so m = D*V
for a) m = 12*5.75 = 69.0 g
for b) 1 mL = 1 cm3 so 30.0 mL = 30 cm3. Using that, m = 30*0.779 = 23.4 g
Travis B. answered 01/13/20
Certified Chemistry Teacher and Tutor with 15+ Years Experience

Jesse E. answered 01/13/20
Masters in Chemistry and Bachelors in Biology
This problem requires the use of manipulating the variables within the density equation: Density(D) = mass(m)/volume(). In part a, we will be substituting the values for density and volume. When we isolate m, we find:
m = D*V = 12 cm3 x 5.75 g/cm3 = 69.0 g. Notice how the units cancel out to leave the units needed
For part b, we need to use the conversion factor 1 ml = 1cm3 and then the problem becomes substituting in values and solving for the mass.
30.0 mL = 30 cm3.
D = m/v Rearranging we get:
m = v * D = 30 cm3. *0.779 g/cm3 = 23.4 g
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Stanton D.
Hi Zera M. , these problems are solved by what's called "dimensional analysis". So, starting with cm^3 of Pd, what do you have to do with a thing like density, in g*cm^-3, to end up with a result in units of g? If you thought it out, and decided "multiply", right you are (cm^3 * g* cm^-3 = g). That's why you always carry units through any calculation in chemistry -- they tell you that you've done the right math operations. "If you take care of your units, your units take care of you!" -- Cheers, -- Mr. d.01/13/20