What is the equation of the line that passes through (–5, 0) and (4, 3)?

Answer 1

To find this answer you will first need to find the slope using slope formula:

y2 - y1

______

x2 -x 1

Your too coordinates following the set up as follows (x1, x2) and (y1,y2)

So for (-5, 0) and (4,3) your x1 = -5, x2=0, y1=4, and y2=3

Next fill in the slope formula with these numbers.

3 - 0

____

4-(-5)

this gives you the slope of 3/9 or 1/3.

Now that we know the slope is 1/3 we need to find our y-intercept. This just means at what number do you touch the y-axis.

To find this we will use the equation

y = mx + b

m is your slope, x will not change, and b is your y-intercept.

we will use one of your coordinates does not matter which one to solve for b.

I will use the coordinate (4,3). Since it is written in (x,y) form we know our x and y to plug in.

so going back to the equation y = mx + b

x = 4

y=3

m = 1/3

b= what we are solving for

3= 1/3(4) + b

3 = 4/3 + b

-4/3 -4/3

-1/3 = b

now we will write the slope form again

y = 1/3x - 1/3