if 40 grams of zinc react with excess hydrochloric acid, how many grams of zinc chloride will be produced?

Answer 1

Zn (s) + 2HCl (aq) ----> ZnCl₂ (aq) + H₂ (g)

40 g Zn x 1.0 mol Zn / 65.39 g Zn = 0.6117 mol Zn

According to the balanced equation, mole ratio of Zn and ZnCl₂ is one to one,

therefore: 0.6117 mol Zn = 0.6117 mol ZnCl₂

0.6117 mol ZnCl₂ x 136.39 g ZnCl₂ / 1.0 mol ZnCl₂ = 83.4 g ZnCl₂