Moses I. answered 01/08/20
PhD-Chemistry Clinic managed by a patient chemistry addict (13 years).
Zn (s) + CuSO4 (aq) → ZnSO4 (aq) + Cu (s)
Can be written as:-
Zn 0 (s) + Cu2+ SO42- (aq) → Zn2+ + SO42-(aq) + Cu0 (s)
You can see now that Zn 0 is changed to Zn2+ increase in oxidation number is OXIDATION!
You can see also that Cu2+ is changed Cu decrease in oxidation number is REDUCTION!
So....Zn is oxidized, Cu 2+ is reduced