find three consecutive even integers such that the first plus 5 times the third is 68

Question

need help solving this math question.

Answer 1

Hi Ninos,

Your numbers are

x

x+2

x+4

first plus 5 times the third is 68

first (x) plus (+) 5 times the third 5(x+4) is = 68

x+5(x+4)=68

x+5x+20=68

6x+20-20=68-20

6x=48

x=8

The numbers are 8, 10, 12