Please hep me on calculus: theorem

Question

If f(x) is differentiable for the closed interval [-3, 2] such that f(-3) = 4 and f(2) = 4, then there exists a value c, -3 < c < 2 such that 

Options:

1. f(c) = 0
2. f '(c) = 0
3. f (c) = 5
4. f '(c) = 5

Answer 1

Since f(a) = f(b), there exists a value c at which f'(c) = 0...