lim x→4 [√(3x+4) - √(4x)]÷[x2 - 4x]
Using L' Hopital's Rule
lim x→4 [(3/2)(3x + 4)(-1/2) - 2(4x)(-1/2)]÷[2x - 4]
[(3/8) - (1/2)]÷(4) = -1/32
Zayn C.
asked • 01/05/20Please help me with calculus!
Find 
Follow
•
1
Add comment
More
Report
1 Expert Answer
Still looking for help? Get the right answer, fast.
Ask a question for free
Get a free answer to a quick problem.
Most questions answered within 4 hours.
OR
Find an Online Tutor Now
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
